The winning Connecticut Play4 numbers for April 17, 2007 were: day 1-9-5-0; night 7-0-5-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Apr 17, 2007 | Night | 7-0-5-5 | 17 | 8 |
| Apr 17, 2007 | Day | 1-9-5-0 | 15 | 6 |
| Apr 16, 2007 | Night | 1-9-6-5 | 21 | 3 |
| Apr 16, 2007 | Day | 4-9-4-0 | 17 | 8 |
| Apr 15, 2007 | Night | 7-5-4-0 | 16 | 7 |
| Apr 14, 2007 | Night | 8-4-1-6 | 19 | 1 |
| Apr 13, 2007 | Night | 4-1-5-1 | 11 | 2 |
| Apr 13, 2007 | Day | 3-9-5-7 | 24 | 6 |
| Apr 12, 2007 | Night | 6-1-2-2 | 11 | 2 |
| Apr 12, 2007 | Day | 2-8-5-9 | 24 | 6 |
| Apr 11, 2007 | Night | 0-5-3-8 | 16 | 7 |
| Apr 11, 2007 | Day | 5-2-9-5 | 21 | 3 |