The winning Connecticut Play4 numbers for March 17, 2007 were: night 1-7-1-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 17, 2007 | Night | 1-7-1-5 | 14 | 5 |
| Mar 16, 2007 | Night | 6-2-3-2 | 13 | 4 |
| Mar 16, 2007 | Day | 2-1-2-5 | 10 | 1 |
| Mar 15, 2007 | Night | 4-4-0-2 | 10 | 1 |
| Mar 15, 2007 | Day | 6-4-9-2 | 21 | 3 |
| Mar 14, 2007 | Night | 1-2-5-1 | 9 | 9 |
| Mar 14, 2007 | Day | 8-1-1-4 | 14 | 5 |
| Mar 13, 2007 | Night | 0-9-2-8 | 19 | 1 |
| Mar 13, 2007 | Day | 4-5-1-7 | 17 | 8 |
| Mar 12, 2007 | Night | 8-9-5-4 | 26 | 8 |
| Mar 12, 2007 | Day | 5-6-9-8 | 28 | 1 |
| Mar 11, 2007 | Night | 4-4-8-2 | 18 | 9 |