The winning Connecticut Play4 numbers for December 19, 2006 were: day 2-1-2-8; night 7-8-5-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 19, 2006 | Night | 7-8-5-0 | 20 | 2 |
| Dec 19, 2006 | Day | 2-1-2-8 | 13 | 4 |
| Dec 18, 2006 | Night | 2-3-8-1 | 14 | 5 |
| Dec 18, 2006 | Day | 0-3-3-6 | 12 | 3 |
| Dec 17, 2006 | Night | 7-2-5-0 | 14 | 5 |
| Dec 16, 2006 | Night | 2-2-5-6 | 15 | 6 |
| Dec 15, 2006 | Night | 1-1-1-0 | 3 | 3 |
| Dec 15, 2006 | Day | 0-8-8-4 | 20 | 2 |
| Dec 14, 2006 | Night | 4-7-1-6 | 18 | 9 |
| Dec 14, 2006 | Day | 5-1-1-1 | 8 | 8 |
| Dec 13, 2006 | Night | 0-5-4-0 | 9 | 9 |
| Dec 13, 2006 | Day | 8-5-5-5 | 23 | 5 |