The winning Connecticut Play4 numbers for December 13, 2006 were: day 8-5-5-5; night 0-5-4-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 13, 2006 | Night | 0-5-4-0 | 9 | 9 |
| Dec 13, 2006 | Day | 8-5-5-5 | 23 | 5 |
| Dec 12, 2006 | Night | 7-3-6-5 | 21 | 3 |
| Dec 12, 2006 | Day | 1-3-5-6 | 15 | 6 |
| Dec 11, 2006 | Night | 4-8-8-3 | 23 | 5 |
| Dec 11, 2006 | Day | 6-3-7-9 | 25 | 7 |
| Dec 10, 2006 | Night | 1-6-3-7 | 17 | 8 |
| Dec 9, 2006 | Night | 7-4-0-7 | 18 | 9 |
| Dec 8, 2006 | Night | 1-4-5-3 | 13 | 4 |
| Dec 8, 2006 | Day | 8-9-7-1 | 25 | 7 |
| Dec 7, 2006 | Night | 0-2-4-9 | 15 | 6 |
| Dec 7, 2006 | Day | 4-9-3-7 | 23 | 5 |