The winning Connecticut Play4 numbers for December 9, 2006 were: night 7-4-0-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 9, 2006 | Night | 7-4-0-7 | 18 | 9 |
| Dec 8, 2006 | Night | 1-4-5-3 | 13 | 4 |
| Dec 8, 2006 | Day | 8-9-7-1 | 25 | 7 |
| Dec 7, 2006 | Night | 0-2-4-9 | 15 | 6 |
| Dec 7, 2006 | Day | 4-9-3-7 | 23 | 5 |
| Dec 6, 2006 | Night | 6-3-7-6 | 22 | 4 |
| Dec 6, 2006 | Day | 7-2-0-5 | 14 | 5 |
| Dec 5, 2006 | Night | 6-7-4-7 | 24 | 6 |
| Dec 5, 2006 | Day | 7-6-9-6 | 28 | 1 |
| Dec 4, 2006 | Night | 5-3-2-9 | 19 | 1 |
| Dec 4, 2006 | Day | 2-1-6-6 | 15 | 6 |
| Dec 3, 2006 | Night | 6-9-2-8 | 25 | 7 |