The winning Connecticut Play4 numbers for November 17, 2006 were: day 3-3-1-0; night 3-9-9-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 17, 2006 | Night | 3-9-9-8 | 29 | 2 |
| Nov 17, 2006 | Day | 3-3-1-0 | 7 | 7 |
| Nov 16, 2006 | Night | 9-8-0-4 | 21 | 3 |
| Nov 16, 2006 | Day | 3-3-5-1 | 12 | 3 |
| Nov 15, 2006 | Night | 2-5-9-8 | 24 | 6 |
| Nov 15, 2006 | Day | 1-8-2-8 | 19 | 1 |
| Nov 14, 2006 | Night | 3-9-6-8 | 26 | 8 |
| Nov 14, 2006 | Day | 1-0-7-3 | 11 | 2 |
| Nov 13, 2006 | Night | 9-9-5-0 | 23 | 5 |
| Nov 13, 2006 | Day | 1-4-3-1 | 9 | 9 |
| Nov 12, 2006 | Night | 2-8-7-6 | 23 | 5 |
| Nov 11, 2006 | Night | 6-7-3-8 | 24 | 6 |