The winning Connecticut Play4 numbers for October 15, 2006 were: night 5-1-8-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 15, 2006 | Night | 5-1-8-5 | 19 | 1 |
| Oct 14, 2006 | Night | 2-4-1-1 | 8 | 8 |
| Oct 13, 2006 | Night | 1-4-8-4 | 17 | 8 |
| Oct 13, 2006 | Day | 8-7-9-8 | 32 | 5 |
| Oct 12, 2006 | Night | 4-4-2-1 | 11 | 2 |
| Oct 12, 2006 | Day | 3-7-9-3 | 22 | 4 |
| Oct 11, 2006 | Night | 8-5-3-5 | 21 | 3 |
| Oct 11, 2006 | Day | 0-6-9-8 | 23 | 5 |
| Oct 10, 2006 | Night | 7-7-9-4 | 27 | 9 |
| Oct 10, 2006 | Day | 9-1-5-7 | 22 | 4 |
| Oct 9, 2006 | Night | 1-9-8-6 | 24 | 6 |
| Oct 9, 2006 | Day | 3-6-7-2 | 18 | 9 |