The winning Connecticut Play4 numbers for September 18, 2006 were: day 9-1-0-7; night 9-2-6-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 18, 2006 | Night | 9-2-6-5 | 22 | 4 |
| Sep 18, 2006 | Day | 9-1-0-7 | 17 | 8 |
| Sep 17, 2006 | Night | 5-0-1-1 | 7 | 7 |
| Sep 16, 2006 | Night | 6-0-5-4 | 15 | 6 |
| Sep 15, 2006 | Night | 2-9-6-0 | 17 | 8 |
| Sep 15, 2006 | Day | 0-9-0-1 | 10 | 1 |
| Sep 14, 2006 | Night | 8-1-8-0 | 17 | 8 |
| Sep 14, 2006 | Day | 0-6-5-8 | 19 | 1 |
| Sep 13, 2006 | Night | 7-7-2-7 | 23 | 5 |
| Sep 13, 2006 | Day | 1-8-5-4 | 18 | 9 |
| Sep 12, 2006 | Night | 1-3-1-4 | 9 | 9 |
| Sep 12, 2006 | Day | 5-7-4-8 | 24 | 6 |