The winning Connecticut Play4 numbers for September 9, 2006 were: night 7-2-9-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 9, 2006 | Night | 7-2-9-4 | 22 | 4 |
| Sep 8, 2006 | Night | 1-0-0-1 | 2 | 2 |
| Sep 8, 2006 | Day | 3-4-0-7 | 14 | 5 |
| Sep 7, 2006 | Night | 9-0-0-5 | 14 | 5 |
| Sep 7, 2006 | Day | 6-9-4-1 | 20 | 2 |
| Sep 6, 2006 | Night | 9-7-8-1 | 25 | 7 |
| Sep 6, 2006 | Day | 8-8-4-8 | 28 | 1 |
| Sep 5, 2006 | Night | 7-8-8-0 | 23 | 5 |
| Sep 5, 2006 | Day | 3-5-9-2 | 19 | 1 |
| Sep 4, 2006 | Night | 1-2-6-5 | 14 | 5 |
| Sep 4, 2006 | Day | 3-9-8-8 | 28 | 1 |
| Sep 3, 2006 | Night | 4-0-6-4 | 14 | 5 |