The winning Connecticut Play4 numbers for March 18, 2006 were: night 3-2-4-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 18, 2006 | Night | 3-2-4-3 | 12 | 3 |
| Mar 17, 2006 | Night | 1-9-3-4 | 17 | 8 |
| Mar 17, 2006 | Day | 7-3-5-5 | 20 | 2 |
| Mar 16, 2006 | Night | 8-4-2-4 | 18 | 9 |
| Mar 16, 2006 | Day | 4-8-1-5 | 18 | 9 |
| Mar 15, 2006 | Night | 8-2-3-7 | 20 | 2 |
| Mar 15, 2006 | Day | 9-6-7-6 | 28 | 1 |
| Mar 14, 2006 | Night | 3-7-9-2 | 21 | 3 |
| Mar 14, 2006 | Day | 9-0-8-4 | 21 | 3 |
| Mar 13, 2006 | Night | 3-6-9-2 | 20 | 2 |
| Mar 13, 2006 | Day | 3-3-7-2 | 15 | 6 |
| Mar 12, 2006 | Night | 4-2-9-1 | 16 | 7 |