The winning Connecticut Play4 numbers for March 12, 2006 were: night 4-2-9-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 12, 2006 | Night | 4-2-9-1 | 16 | 7 |
| Mar 11, 2006 | Night | 8-8-0-6 | 22 | 4 |
| Mar 10, 2006 | Night | 2-5-1-5 | 13 | 4 |
| Mar 10, 2006 | Day | 1-8-3-4 | 16 | 7 |
| Mar 9, 2006 | Night | 7-0-9-8 | 24 | 6 |
| Mar 9, 2006 | Day | 8-0-3-6 | 17 | 8 |
| Mar 8, 2006 | Night | 5-9-0-4 | 18 | 9 |
| Mar 8, 2006 | Day | 0-1-1-7 | 9 | 9 |
| Mar 7, 2006 | Night | 1-4-8-1 | 14 | 5 |
| Mar 7, 2006 | Day | 5-7-8-4 | 24 | 6 |
| Mar 6, 2006 | Night | 9-7-8-7 | 31 | 4 |
| Mar 6, 2006 | Day | 9-5-9-6 | 29 | 2 |