The winning Connecticut Play4 numbers for December 26, 2005 were: day 9-7-3-2; night 6-3-7-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 26, 2005 | Night | 6-3-7-3 | 19 | 1 |
| Dec 26, 2005 | Day | 9-7-3-2 | 21 | 3 |
| Dec 25, 2005 | Night | 1-8-8-6 | 23 | 5 |
| Dec 24, 2005 | Night | 6-6-0-1 | 13 | 4 |
| Dec 23, 2005 | Night | 6-4-6-0 | 16 | 7 |
| Dec 23, 2005 | Day | 1-1-7-3 | 12 | 3 |
| Dec 22, 2005 | Night | 5-4-6-7 | 22 | 4 |
| Dec 22, 2005 | Day | 8-8-8-8 | 32 | 5 |
| Dec 21, 2005 | Night | 3-9-4-0 | 16 | 7 |
| Dec 21, 2005 | Day | 8-5-2-5 | 20 | 2 |
| Dec 20, 2005 | Night | 5-6-3-8 | 22 | 4 |
| Dec 20, 2005 | Day | 3-7-5-5 | 20 | 2 |