The winning Connecticut Play4 numbers for December 18, 2005 were: night 2-6-7-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 18, 2005 | Night | 2-6-7-7 | 22 | 4 |
| Dec 17, 2005 | Night | 6-4-5-3 | 18 | 9 |
| Dec 16, 2005 | Night | 0-8-2-8 | 18 | 9 |
| Dec 16, 2005 | Day | 3-2-2-9 | 16 | 7 |
| Dec 15, 2005 | Night | 8-2-5-5 | 20 | 2 |
| Dec 15, 2005 | Day | 0-0-9-3 | 12 | 3 |
| Dec 14, 2005 | Night | 9-5-0-8 | 22 | 4 |
| Dec 14, 2005 | Day | 3-0-0-3 | 6 | 6 |
| Dec 13, 2005 | Night | 1-0-6-1 | 8 | 8 |
| Dec 13, 2005 | Day | 1-9-2-8 | 20 | 2 |
| Dec 12, 2005 | Night | 5-6-0-9 | 20 | 2 |
| Dec 12, 2005 | Day | 3-2-6-3 | 14 | 5 |