The winning Connecticut Play4 numbers for December 11, 2005 were: night 8-4-9-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 11, 2005 | Night | 8-4-9-1 | 22 | 4 |
| Dec 10, 2005 | Night | 5-1-6-6 | 18 | 9 |
| Dec 9, 2005 | Night | 7-0-0-2 | 9 | 9 |
| Dec 9, 2005 | Day | 9-7-2-5 | 23 | 5 |
| Dec 8, 2005 | Night | 4-9-3-3 | 19 | 1 |
| Dec 8, 2005 | Day | 5-2-3-5 | 15 | 6 |
| Dec 7, 2005 | Night | 8-8-1-0 | 17 | 8 |
| Dec 7, 2005 | Day | 1-5-5-9 | 20 | 2 |
| Dec 6, 2005 | Night | 6-9-5-7 | 27 | 9 |
| Dec 6, 2005 | Day | 7-1-8-1 | 17 | 8 |
| Dec 5, 2005 | Night | 8-8-1-1 | 18 | 9 |
| Dec 5, 2005 | Day | 1-8-8-8 | 25 | 7 |