The winning Connecticut Play4 numbers for December 2, 2005 were: day 3-0-5-2; night 3-4-5-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 2, 2005 | Night | 3-4-5-3 | 15 | 6 |
| Dec 2, 2005 | Day | 3-0-5-2 | 10 | 1 |
| Dec 1, 2005 | Night | 1-1-0-9 | 11 | 2 |
| Dec 1, 2005 | Day | 3-0-8-6 | 17 | 8 |
| Nov 30, 2005 | Night | 8-4-6-5 | 23 | 5 |
| Nov 30, 2005 | Day | 5-9-8-9 | 31 | 4 |
| Nov 29, 2005 | Night | 6-2-9-4 | 21 | 3 |
| Nov 29, 2005 | Day | 4-1-0-8 | 13 | 4 |
| Nov 28, 2005 | Night | 1-0-6-8 | 15 | 6 |
| Nov 28, 2005 | Day | 0-1-9-9 | 19 | 1 |
| Nov 27, 2005 | Night | 3-0-2-9 | 14 | 5 |
| Nov 26, 2005 | Night | 1-2-3-4 | 10 | 1 |