The winning Connecticut Play4 numbers for October 29, 2005 were: night 2-2-2-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 29, 2005 | Night | 2-2-2-9 | 15 | 6 |
| Oct 28, 2005 | Night | 8-8-4-6 | 26 | 8 |
| Oct 28, 2005 | Day | 5-5-0-0 | 10 | 1 |
| Oct 27, 2005 | Night | 5-8-0-2 | 15 | 6 |
| Oct 27, 2005 | Day | 1-9-2-6 | 18 | 9 |
| Oct 26, 2005 | Night | 6-7-1-5 | 19 | 1 |
| Oct 26, 2005 | Day | 9-5-8-3 | 25 | 7 |
| Oct 25, 2005 | Night | 3-3-9-7 | 22 | 4 |
| Oct 25, 2005 | Day | 3-8-7-3 | 21 | 3 |
| Oct 24, 2005 | Night | 0-7-4-8 | 19 | 1 |
| Oct 24, 2005 | Day | 8-0-9-4 | 21 | 3 |
| Oct 23, 2005 | Night | 7-5-1-2 | 15 | 6 |