The winning Connecticut Play4 numbers for October 23, 2005 were: night 7-5-1-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 23, 2005 | Night | 7-5-1-2 | 15 | 6 |
| Oct 22, 2005 | Night | 1-1-4-8 | 14 | 5 |
| Oct 21, 2005 | Night | 2-0-3-7 | 12 | 3 |
| Oct 21, 2005 | Day | 9-1-1-3 | 14 | 5 |
| Oct 20, 2005 | Night | 9-7-7-0 | 23 | 5 |
| Oct 20, 2005 | Day | 7-4-8-2 | 21 | 3 |
| Oct 19, 2005 | Night | 3-3-3-5 | 14 | 5 |
| Oct 19, 2005 | Day | 2-2-3-1 | 8 | 8 |
| Oct 18, 2005 | Night | 6-4-8-4 | 22 | 4 |
| Oct 18, 2005 | Day | 0-8-6-6 | 20 | 2 |
| Oct 17, 2005 | Night | 1-3-6-8 | 18 | 9 |
| Oct 17, 2005 | Day | 4-4-3-2 | 13 | 4 |