The winning Connecticut Play4 numbers for October 12, 2005 were: day 2-9-8-8; night 0-8-9-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 12, 2005 | Night | 0-8-9-3 | 20 | 2 |
| Oct 12, 2005 | Day | 2-9-8-8 | 27 | 9 |
| Oct 11, 2005 | Night | 3-1-7-0 | 11 | 2 |
| Oct 11, 2005 | Day | 0-2-1-2 | 5 | 5 |
| Oct 10, 2005 | Night | 8-8-0-0 | 16 | 7 |
| Oct 10, 2005 | Day | 8-3-5-5 | 21 | 3 |
| Oct 9, 2005 | Night | 6-4-4-9 | 23 | 5 |
| Oct 8, 2005 | Night | 5-2-8-3 | 18 | 9 |
| Oct 7, 2005 | Night | 4-0-4-4 | 12 | 3 |
| Oct 7, 2005 | Day | 2-4-7-4 | 17 | 8 |
| Oct 6, 2005 | Night | 2-3-8-3 | 16 | 7 |
| Oct 6, 2005 | Day | 4-5-2-3 | 14 | 5 |