The winning Connecticut Play4 numbers for October 7, 2005 were: day 2-4-7-4; night 4-0-4-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 7, 2005 | Night | 4-0-4-4 | 12 | 3 |
| Oct 7, 2005 | Day | 2-4-7-4 | 17 | 8 |
| Oct 6, 2005 | Night | 2-3-8-3 | 16 | 7 |
| Oct 6, 2005 | Day | 4-5-2-3 | 14 | 5 |
| Oct 5, 2005 | Night | 5-5-3-0 | 13 | 4 |
| Oct 5, 2005 | Day | 3-5-0-7 | 15 | 6 |
| Oct 4, 2005 | Night | 3-4-1-1 | 9 | 9 |
| Oct 4, 2005 | Day | 4-4-4-4 | 16 | 7 |
| Oct 3, 2005 | Night | 0-3-0-0 | 3 | 3 |
| Oct 3, 2005 | Day | 3-5-0-8 | 16 | 7 |
| Oct 2, 2005 | Night | 3-7-4-5 | 19 | 1 |
| Oct 1, 2005 | Night | 6-9-8-2 | 25 | 7 |