The winning Connecticut Play4 numbers for September 15, 2005 were: day 2-4-0-0; night 2-9-3-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 15, 2005 | Night | 2-9-3-9 | 23 | 5 |
| Sep 15, 2005 | Day | 2-4-0-0 | 6 | 6 |
| Sep 14, 2005 | Night | 2-9-8-0 | 19 | 1 |
| Sep 14, 2005 | Day | 9-2-4-0 | 15 | 6 |
| Sep 13, 2005 | Night | 7-3-9-8 | 27 | 9 |
| Sep 13, 2005 | Day | 7-7-4-4 | 22 | 4 |
| Sep 12, 2005 | Night | 1-9-6-7 | 23 | 5 |
| Sep 12, 2005 | Day | 7-1-1-9 | 18 | 9 |
| Sep 11, 2005 | Night | 2-8-2-8 | 20 | 2 |
| Sep 10, 2005 | Night | 9-6-4-5 | 24 | 6 |
| Sep 9, 2005 | Night | 3-0-6-6 | 15 | 6 |
| Sep 9, 2005 | Day | 8-3-4-9 | 24 | 6 |