The winning Connecticut Play4 numbers for September 10, 2005 were: night 9-6-4-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 10, 2005 | Night | 9-6-4-5 | 24 | 6 |
| Sep 9, 2005 | Night | 3-0-6-6 | 15 | 6 |
| Sep 9, 2005 | Day | 8-3-4-9 | 24 | 6 |
| Sep 8, 2005 | Night | 3-1-9-2 | 15 | 6 |
| Sep 8, 2005 | Day | 4-1-8-2 | 15 | 6 |
| Sep 7, 2005 | Night | 0-1-6-8 | 15 | 6 |
| Sep 7, 2005 | Day | 6-3-2-1 | 12 | 3 |
| Sep 6, 2005 | Night | 7-5-9-2 | 23 | 5 |
| Sep 6, 2005 | Day | 0-0-7-9 | 16 | 7 |
| Sep 5, 2005 | Night | 9-1-5-8 | 23 | 5 |
| Sep 5, 2005 | Day | 8-9-7-8 | 32 | 5 |
| Sep 4, 2005 | Night | 6-4-3-4 | 17 | 8 |