The winning Connecticut Play4 numbers for September 4, 2005 were: night 6-4-3-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 4, 2005 | Night | 6-4-3-4 | 17 | 8 |
| Sep 3, 2005 | Night | 6-1-3-2 | 12 | 3 |
| Sep 2, 2005 | Night | 9-0-7-9 | 25 | 7 |
| Sep 2, 2005 | Day | 6-2-2-1 | 11 | 2 |
| Sep 1, 2005 | Night | 3-7-3-0 | 13 | 4 |
| Sep 1, 2005 | Day | 6-7-4-1 | 18 | 9 |
| Aug 31, 2005 | Night | 5-8-4-6 | 23 | 5 |
| Aug 31, 2005 | Day | 0-8-1-0 | 9 | 9 |
| Aug 30, 2005 | Night | 9-8-0-1 | 18 | 9 |
| Aug 30, 2005 | Day | 0-4-0-7 | 11 | 2 |
| Aug 29, 2005 | Night | 1-0-5-7 | 13 | 4 |
| Aug 29, 2005 | Day | 2-0-9-4 | 15 | 6 |