The winning Connecticut Play4 numbers for August 27, 2005 were: night 9-1-3-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 27, 2005 | Night | 9-1-3-4 | 17 | 8 |
| Aug 26, 2005 | Night | 6-9-4-3 | 22 | 4 |
| Aug 26, 2005 | Day | 8-9-3-9 | 29 | 2 |
| Aug 25, 2005 | Night | 1-2-8-5 | 16 | 7 |
| Aug 25, 2005 | Day | 8-9-9-0 | 26 | 8 |
| Aug 24, 2005 | Night | 7-2-1-8 | 18 | 9 |
| Aug 24, 2005 | Day | 9-8-6-1 | 24 | 6 |
| Aug 23, 2005 | Night | 1-9-9-6 | 25 | 7 |
| Aug 23, 2005 | Day | 7-5-5-8 | 25 | 7 |
| Aug 22, 2005 | Night | 7-1-1-7 | 16 | 7 |
| Aug 22, 2005 | Day | 4-9-1-9 | 23 | 5 |
| Aug 21, 2005 | Night | 0-1-5-1 | 7 | 7 |