The winning Connecticut Play4 numbers for August 7, 2005 were: night 2-4-9-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 7, 2005 | Night | 2-4-9-1 | 16 | 7 |
| Aug 6, 2005 | Night | 7-2-7-9 | 25 | 7 |
| Aug 5, 2005 | Night | 4-7-0-4 | 15 | 6 |
| Aug 5, 2005 | Day | 9-9-8-7 | 33 | 6 |
| Aug 4, 2005 | Night | 2-9-9-8 | 28 | 1 |
| Aug 4, 2005 | Day | 7-3-3-3 | 16 | 7 |
| Aug 3, 2005 | Night | 8-2-6-4 | 20 | 2 |
| Aug 3, 2005 | Day | 2-6-2-2 | 12 | 3 |
| Aug 2, 2005 | Night | 1-0-6-7 | 14 | 5 |
| Aug 2, 2005 | Day | 9-0-3-8 | 20 | 2 |
| Aug 1, 2005 | Night | 5-1-9-7 | 22 | 4 |
| Aug 1, 2005 | Day | 5-4-1-6 | 16 | 7 |