The winning Connecticut Play4 numbers for March 27, 2005 were: night 5-6-2-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 27, 2005 | Night | 5-6-2-6 | 19 | 1 |
| Mar 26, 2005 | Night | 9-1-2-5 | 17 | 8 |
| Mar 25, 2005 | Night | 5-6-3-8 | 22 | 4 |
| Mar 25, 2005 | Day | 1-4-4-9 | 18 | 9 |
| Mar 24, 2005 | Night | 3-8-5-9 | 25 | 7 |
| Mar 24, 2005 | Day | 8-0-1-4 | 13 | 4 |
| Mar 23, 2005 | Night | 2-1-2-2 | 7 | 7 |
| Mar 23, 2005 | Day | 5-1-8-8 | 22 | 4 |
| Mar 22, 2005 | Night | 4-8-0-8 | 20 | 2 |
| Mar 22, 2005 | Day | 4-5-9-3 | 21 | 3 |
| Mar 21, 2005 | Night | 9-9-3-0 | 21 | 3 |
| Mar 21, 2005 | Day | 9-3-7-7 | 26 | 8 |