The winning Connecticut Play4 numbers for March 19, 2005 were: night 9-1-8-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 19, 2005 | Night | 9-1-8-2 | 20 | 2 |
| Mar 18, 2005 | Night | 5-9-6-6 | 26 | 8 |
| Mar 18, 2005 | Day | 3-4-4-7 | 18 | 9 |
| Mar 17, 2005 | Night | 4-0-8-6 | 18 | 9 |
| Mar 17, 2005 | Day | 9-2-0-6 | 17 | 8 |
| Mar 16, 2005 | Night | 2-1-2-6 | 11 | 2 |
| Mar 16, 2005 | Day | 5-6-9-2 | 22 | 4 |
| Mar 15, 2005 | Night | 7-8-1-0 | 16 | 7 |
| Mar 15, 2005 | Day | 5-4-9-9 | 27 | 9 |
| Mar 14, 2005 | Night | 5-3-3-9 | 20 | 2 |
| Mar 14, 2005 | Day | 8-8-0-2 | 18 | 9 |
| Mar 13, 2005 | Night | 9-2-4-5 | 20 | 2 |