The winning Connecticut Play4 numbers for March 12, 2005 were: night 4-3-4-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 12, 2005 | Night | 4-3-4-0 | 11 | 2 |
| Mar 11, 2005 | Night | 8-6-9-1 | 24 | 6 |
| Mar 11, 2005 | Day | 4-8-8-1 | 21 | 3 |
| Mar 10, 2005 | Night | 2-5-0-6 | 13 | 4 |
| Mar 10, 2005 | Day | 2-1-5-1 | 9 | 9 |
| Mar 9, 2005 | Night | 6-8-5-0 | 19 | 1 |
| Mar 9, 2005 | Day | 9-9-3-5 | 26 | 8 |
| Mar 8, 2005 | Night | 1-6-3-2 | 12 | 3 |
| Mar 8, 2005 | Day | 8-7-5-1 | 21 | 3 |
| Mar 7, 2005 | Night | 8-7-2-7 | 24 | 6 |
| Mar 7, 2005 | Day | 8-5-4-5 | 22 | 4 |
| Mar 6, 2005 | Night | 5-2-1-0 | 8 | 8 |