The winning Connecticut Play4 numbers for March 5, 2005 were: night 8-1-2-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 5, 2005 | Night | 8-1-2-9 | 20 | 2 |
| Mar 4, 2005 | Night | 0-1-7-2 | 10 | 1 |
| Mar 4, 2005 | Day | 7-4-1-1 | 13 | 4 |
| Mar 3, 2005 | Night | 5-1-9-3 | 18 | 9 |
| Mar 3, 2005 | Day | 9-3-3-4 | 19 | 1 |
| Mar 2, 2005 | Night | 5-7-2-0 | 14 | 5 |
| Mar 2, 2005 | Day | 9-6-8-3 | 26 | 8 |
| Mar 1, 2005 | Night | 2-9-2-8 | 21 | 3 |
| Mar 1, 2005 | Day | 1-1-6-6 | 14 | 5 |
| Feb 28, 2005 | Night | 5-5-0-7 | 17 | 8 |
| Feb 28, 2005 | Day | 8-4-3-1 | 16 | 7 |
| Feb 27, 2005 | Night | 7-4-8-0 | 19 | 1 |