The winning Connecticut Play4 numbers for February 13, 2005 were: night 8-2-2-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Feb 13, 2005 | Night | 8-2-2-9 | 21 | 3 |
| Feb 12, 2005 | Night | 1-3-4-7 | 15 | 6 |
| Feb 11, 2005 | Night | 0-1-7-3 | 11 | 2 |
| Feb 11, 2005 | Day | 3-5-0-7 | 15 | 6 |
| Feb 10, 2005 | Night | 9-0-2-3 | 14 | 5 |
| Feb 10, 2005 | Day | 6-6-8-8 | 28 | 1 |
| Feb 9, 2005 | Night | 1-9-0-6 | 16 | 7 |
| Feb 9, 2005 | Day | 8-4-2-2 | 16 | 7 |
| Feb 8, 2005 | Night | 4-3-4-0 | 11 | 2 |
| Feb 8, 2005 | Day | 9-2-6-5 | 22 | 4 |
| Feb 7, 2005 | Night | 9-9-3-7 | 28 | 1 |
| Feb 7, 2005 | Day | 0-7-8-6 | 21 | 3 |