The winning Connecticut Play4 numbers for December 25, 2004 were: night 0-7-0-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 25, 2004 | Night | 0-7-0-5 | 12 | 3 |
| Dec 24, 2004 | Night | 5-9-4-9 | 27 | 9 |
| Dec 24, 2004 | Day | 9-9-1-0 | 19 | 1 |
| Dec 23, 2004 | Night | 9-3-9-2 | 23 | 5 |
| Dec 23, 2004 | Day | 3-8-7-0 | 18 | 9 |
| Dec 22, 2004 | Night | 9-7-3-9 | 28 | 1 |
| Dec 22, 2004 | Day | 9-4-5-4 | 22 | 4 |
| Dec 21, 2004 | Night | 1-3-0-4 | 8 | 8 |
| Dec 21, 2004 | Day | 0-7-8-6 | 21 | 3 |
| Dec 20, 2004 | Night | 8-1-3-6 | 18 | 9 |
| Dec 20, 2004 | Day | 7-0-6-6 | 19 | 1 |
| Dec 19, 2004 | Night | 7-3-3-1 | 14 | 5 |