The winning Connecticut Play4 numbers for December 19, 2004 were: night 7-3-3-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 19, 2004 | Night | 7-3-3-1 | 14 | 5 |
| Dec 18, 2004 | Night | 2-5-5-5 | 17 | 8 |
| Dec 17, 2004 | Night | 5-8-3-9 | 25 | 7 |
| Dec 17, 2004 | Day | 4-9-3-0 | 16 | 7 |
| Dec 16, 2004 | Night | 8-8-9-9 | 34 | 7 |
| Dec 16, 2004 | Day | 4-9-9-2 | 24 | 6 |
| Dec 15, 2004 | Night | 5-4-4-7 | 20 | 2 |
| Dec 15, 2004 | Day | 9-6-4-3 | 22 | 4 |
| Dec 14, 2004 | Night | 1-1-0-2 | 4 | 4 |
| Dec 14, 2004 | Day | 0-3-4-6 | 13 | 4 |
| Dec 13, 2004 | Night | 1-1-1-2 | 5 | 5 |
| Dec 13, 2004 | Day | 1-2-2-0 | 5 | 5 |