The winning Connecticut Play4 numbers for December 5, 2004 were: night 6-8-7-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 5, 2004 | Night | 6-8-7-5 | 26 | 8 |
| Dec 4, 2004 | Night | 7-4-0-9 | 20 | 2 |
| Dec 3, 2004 | Night | 3-1-0-1 | 5 | 5 |
| Dec 3, 2004 | Day | 9-9-8-8 | 34 | 7 |
| Dec 2, 2004 | Night | 1-2-3-7 | 13 | 4 |
| Dec 2, 2004 | Day | 3-5-8-9 | 25 | 7 |
| Dec 1, 2004 | Night | 8-1-4-6 | 19 | 1 |
| Dec 1, 2004 | Day | 2-5-0-0 | 7 | 7 |
| Nov 30, 2004 | Night | 9-5-4-2 | 20 | 2 |
| Nov 30, 2004 | Day | 6-6-4-4 | 20 | 2 |
| Nov 29, 2004 | Night | 7-1-4-1 | 13 | 4 |
| Nov 29, 2004 | Day | 4-6-6-4 | 20 | 2 |