The winning Connecticut Play4 numbers for November 29, 2003 were: night 8-2-7-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 29, 2003 | Night | 8-2-7-8 | 25 | 7 |
| Nov 28, 2003 | Night | 1-4-5-3 | 13 | 4 |
| Nov 28, 2003 | Day | 7-3-3-4 | 17 | 8 |
| Nov 27, 2003 | Night | 0-1-5-0 | 6 | 6 |
| Nov 27, 2003 | Day | 1-8-1-2 | 12 | 3 |
| Nov 26, 2003 | Night | 7-1-9-9 | 26 | 8 |
| Nov 26, 2003 | Day | 4-2-5-4 | 15 | 6 |
| Nov 25, 2003 | Night | 8-5-5-1 | 19 | 1 |
| Nov 25, 2003 | Day | 8-6-5-0 | 19 | 1 |
| Nov 24, 2003 | Night | 9-8-0-2 | 19 | 1 |
| Nov 24, 2003 | Day | 9-3-0-8 | 20 | 2 |
| Nov 23, 2003 | Night | 4-8-5-5 | 22 | 4 |