The winning Connecticut Play4 numbers for October 26, 2003 were: night 6-6-7-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 26, 2003 | Night | 6-6-7-5 | 24 | 6 |
| Oct 25, 2003 | Night | 0-4-8-2 | 14 | 5 |
| Oct 24, 2003 | Night | 3-2-8-0 | 13 | 4 |
| Oct 24, 2003 | Day | 0-8-7-3 | 18 | 9 |
| Oct 23, 2003 | Night | 1-9-9-3 | 22 | 4 |
| Oct 23, 2003 | Day | 8-2-3-9 | 22 | 4 |
| Oct 22, 2003 | Night | 4-7-3-1 | 15 | 6 |
| Oct 22, 2003 | Day | 3-1-4-0 | 8 | 8 |
| Oct 21, 2003 | Night | 4-1-2-6 | 13 | 4 |
| Oct 21, 2003 | Day | 2-5-7-7 | 21 | 3 |
| Oct 20, 2003 | Night | 8-6-4-0 | 18 | 9 |
| Oct 20, 2003 | Day | 0-7-5-8 | 20 | 2 |