The winning Connecticut Play4 numbers for September 29, 2003 were: day 3-8-7-1; night 2-6-3-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 29, 2003 | Night | 2-6-3-9 | 20 | 2 |
| Sep 29, 2003 | Day | 3-8-7-1 | 19 | 1 |
| Sep 28, 2003 | Night | 1-5-4-3 | 13 | 4 |
| Sep 27, 2003 | Night | 6-1-2-8 | 17 | 8 |
| Sep 26, 2003 | Night | 0-1-7-5 | 13 | 4 |
| Sep 26, 2003 | Day | 9-3-5-7 | 24 | 6 |
| Sep 25, 2003 | Night | 6-1-2-4 | 13 | 4 |
| Sep 25, 2003 | Day | 6-9-2-5 | 22 | 4 |
| Sep 24, 2003 | Night | 9-3-4-4 | 20 | 2 |
| Sep 24, 2003 | Day | 6-9-3-0 | 18 | 9 |
| Sep 23, 2003 | Night | 9-5-4-0 | 18 | 9 |
| Sep 23, 2003 | Day | 8-0-5-9 | 22 | 4 |