The winning Connecticut Play4 numbers for September 12, 2003 were: day 7-3-8-8; night 7-5-5-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 12, 2003 | Night | 7-5-5-6 | 23 | 5 |
| Sep 12, 2003 | Day | 7-3-8-8 | 26 | 8 |
| Sep 11, 2003 | Night | 5-2-3-6 | 16 | 7 |
| Sep 11, 2003 | Day | 0-4-1-9 | 14 | 5 |
| Sep 10, 2003 | Night | 6-5-6-7 | 24 | 6 |
| Sep 10, 2003 | Day | 0-8-8-1 | 17 | 8 |
| Sep 9, 2003 | Night | 3-4-4-3 | 14 | 5 |
| Sep 9, 2003 | Day | 4-2-4-3 | 13 | 4 |
| Sep 8, 2003 | Night | 1-4-7-5 | 17 | 8 |
| Sep 8, 2003 | Day | 7-0-6-1 | 14 | 5 |
| Sep 7, 2003 | Night | 3-8-4-4 | 19 | 1 |
| Sep 6, 2003 | Night | 2-4-7-9 | 22 | 4 |