The winning Connecticut Play4 numbers for September 8, 2003 were: day 7-0-6-1; night 1-4-7-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 8, 2003 | Night | 1-4-7-5 | 17 | 8 |
| Sep 8, 2003 | Day | 7-0-6-1 | 14 | 5 |
| Sep 7, 2003 | Night | 3-8-4-4 | 19 | 1 |
| Sep 6, 2003 | Night | 2-4-7-9 | 22 | 4 |
| Sep 5, 2003 | Night | 1-7-6-0 | 14 | 5 |
| Sep 5, 2003 | Day | 1-0-0-9 | 10 | 1 |
| Sep 4, 2003 | Night | 2-7-1-3 | 13 | 4 |
| Sep 4, 2003 | Day | 2-5-7-5 | 19 | 1 |
| Sep 3, 2003 | Night | 6-7-5-0 | 18 | 9 |
| Sep 3, 2003 | Day | 2-7-4-2 | 15 | 6 |
| Sep 2, 2003 | Night | 4-4-6-4 | 18 | 9 |
| Sep 2, 2003 | Day | 1-2-2-3 | 8 | 8 |