The winning Connecticut Play4 numbers for September 4, 2003 were: day 2-5-7-5; night 2-7-1-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 4, 2003 | Night | 2-7-1-3 | 13 | 4 |
| Sep 4, 2003 | Day | 2-5-7-5 | 19 | 1 |
| Sep 3, 2003 | Night | 6-7-5-0 | 18 | 9 |
| Sep 3, 2003 | Day | 2-7-4-2 | 15 | 6 |
| Sep 2, 2003 | Night | 4-4-6-4 | 18 | 9 |
| Sep 2, 2003 | Day | 1-2-2-3 | 8 | 8 |
| Sep 1, 2003 | Night | 8-2-8-4 | 22 | 4 |
| Sep 1, 2003 | Day | 4-4-1-7 | 16 | 7 |
| Aug 31, 2003 | Night | 5-0-2-4 | 11 | 2 |
| Aug 30, 2003 | Night | 9-4-4-7 | 24 | 6 |
| Aug 29, 2003 | Night | 3-9-0-5 | 17 | 8 |
| Aug 29, 2003 | Day | 4-9-3-9 | 25 | 7 |