The winning Connecticut Play4 numbers for August 25, 2003 were: day 3-0-7-2; night 1-5-4-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 25, 2003 | Night | 1-5-4-4 | 14 | 5 |
| Aug 25, 2003 | Day | 3-0-7-2 | 12 | 3 |
| Aug 24, 2003 | Night | 3-0-9-4 | 16 | 7 |
| Aug 23, 2003 | Night | 5-5-8-4 | 22 | 4 |
| Aug 22, 2003 | Night | 4-0-5-7 | 16 | 7 |
| Aug 22, 2003 | Day | 5-4-9-3 | 21 | 3 |
| Aug 21, 2003 | Night | 7-3-5-6 | 21 | 3 |
| Aug 21, 2003 | Day | 4-1-9-0 | 14 | 5 |
| Aug 20, 2003 | Night | 9-5-0-1 | 15 | 6 |
| Aug 20, 2003 | Day | 7-7-6-9 | 29 | 2 |
| Aug 19, 2003 | Night | 3-9-1-7 | 20 | 2 |
| Aug 19, 2003 | Day | 2-6-3-4 | 15 | 6 |