The winning Connecticut Play4 numbers for August 18, 2003 were: day 3-5-0-5; night 6-5-1-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 18, 2003 | Night | 6-5-1-2 | 14 | 5 |
| Aug 18, 2003 | Day | 3-5-0-5 | 13 | 4 |
| Aug 17, 2003 | Night | 9-1-4-7 | 21 | 3 |
| Aug 16, 2003 | Night | 9-6-6-0 | 21 | 3 |
| Aug 15, 2003 | Night | 0-9-9-5 | 23 | 5 |
| Aug 15, 2003 | Day | 4-8-6-9 | 27 | 9 |
| Aug 14, 2003 | Night | 9-1-1-4 | 15 | 6 |
| Aug 14, 2003 | Day | 5-9-0-8 | 22 | 4 |
| Aug 13, 2003 | Night | 9-4-3-1 | 17 | 8 |
| Aug 13, 2003 | Day | 6-4-0-1 | 11 | 2 |
| Aug 12, 2003 | Night | 4-8-7-4 | 23 | 5 |
| Aug 12, 2003 | Day | 8-2-6-9 | 25 | 7 |