The winning Connecticut Play4 numbers for August 12, 2003 were: day 8-2-6-9; night 4-8-7-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 12, 2003 | Night | 4-8-7-4 | 23 | 5 |
| Aug 12, 2003 | Day | 8-2-6-9 | 25 | 7 |
| Aug 11, 2003 | Night | 8-6-7-3 | 24 | 6 |
| Aug 11, 2003 | Day | 2-1-9-8 | 20 | 2 |
| Aug 10, 2003 | Night | 0-3-5-2 | 10 | 1 |
| Aug 9, 2003 | Night | 8-7-2-1 | 18 | 9 |
| Aug 8, 2003 | Night | 2-8-5-1 | 16 | 7 |
| Aug 8, 2003 | Day | 1-4-7-8 | 20 | 2 |
| Aug 7, 2003 | Night | 6-0-7-8 | 21 | 3 |
| Aug 7, 2003 | Day | 8-8-6-1 | 23 | 5 |
| Aug 6, 2003 | Night | 9-9-9-7 | 34 | 7 |
| Aug 6, 2003 | Day | 6-9-3-0 | 18 | 9 |