The winning Connecticut Play4 numbers for July 12, 2003 were: night 3-6-4-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 12, 2003 | Night | 3-6-4-7 | 20 | 2 |
| Jul 11, 2003 | Night | 5-1-4-0 | 10 | 1 |
| Jul 11, 2003 | Day | 0-4-8-4 | 16 | 7 |
| Jul 10, 2003 | Night | 5-1-2-0 | 8 | 8 |
| Jul 10, 2003 | Day | 1-7-7-2 | 17 | 8 |
| Jul 9, 2003 | Night | 1-8-1-7 | 17 | 8 |
| Jul 9, 2003 | Day | 6-2-9-3 | 20 | 2 |
| Jul 8, 2003 | Night | 3-0-7-1 | 11 | 2 |
| Jul 8, 2003 | Day | 8-8-7-3 | 26 | 8 |
| Jul 7, 2003 | Night | 4-6-3-3 | 16 | 7 |
| Jul 7, 2003 | Day | 8-8-1-4 | 21 | 3 |
| Jul 6, 2003 | Night | 5-2-9-3 | 19 | 1 |