The winning Connecticut Play4 numbers for June 7, 2003 were: night 9-1-2-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jun 7, 2003 | Night | 9-1-2-3 | 15 | 6 |
| Jun 6, 2003 | Night | 3-4-1-0 | 8 | 8 |
| Jun 6, 2003 | Day | 0-3-3-3 | 9 | 9 |
| Jun 5, 2003 | Night | 2-8-3-8 | 21 | 3 |
| Jun 5, 2003 | Day | 1-0-9-0 | 10 | 1 |
| Jun 4, 2003 | Night | 7-4-4-3 | 18 | 9 |
| Jun 4, 2003 | Day | 7-8-8-5 | 28 | 1 |
| Jun 3, 2003 | Night | 4-1-8-0 | 13 | 4 |
| Jun 3, 2003 | Day | 3-1-1-6 | 11 | 2 |
| Jun 2, 2003 | Night | 9-4-5-2 | 20 | 2 |
| Jun 2, 2003 | Day | 7-7-9-8 | 31 | 4 |
| Jun 1, 2003 | Night | 1-0-0-0 | 1 | 1 |