The winning Connecticut Play4 numbers for March 22, 2003 were: night 6-0-6-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 22, 2003 | Night | 6-0-6-8 | 20 | 2 |
| Mar 21, 2003 | Night | 6-2-5-4 | 17 | 8 |
| Mar 21, 2003 | Day | 2-5-0-0 | 7 | 7 |
| Mar 20, 2003 | Night | 1-4-5-8 | 18 | 9 |
| Mar 20, 2003 | Day | 1-3-3-5 | 12 | 3 |
| Mar 19, 2003 | Night | 9-7-8-7 | 31 | 4 |
| Mar 19, 2003 | Day | 3-6-1-4 | 14 | 5 |
| Mar 18, 2003 | Night | 6-8-6-2 | 22 | 4 |
| Mar 18, 2003 | Day | 8-0-9-7 | 24 | 6 |
| Mar 17, 2003 | Night | 2-0-2-6 | 10 | 1 |
| Mar 17, 2003 | Day | 9-9-8-7 | 33 | 6 |
| Mar 16, 2003 | Night | 1-2-2-2 | 7 | 7 |