The winning Connecticut Play4 numbers for March 17, 2003 were: day 9-9-8-7; night 2-0-2-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 17, 2003 | Night | 2-0-2-6 | 10 | 1 |
| Mar 17, 2003 | Day | 9-9-8-7 | 33 | 6 |
| Mar 16, 2003 | Night | 1-2-2-2 | 7 | 7 |
| Mar 15, 2003 | Night | 9-9-8-1 | 27 | 9 |
| Mar 14, 2003 | Night | 1-2-5-3 | 11 | 2 |
| Mar 14, 2003 | Day | 4-6-0-3 | 13 | 4 |
| Mar 13, 2003 | Night | 0-9-2-6 | 17 | 8 |
| Mar 13, 2003 | Day | 7-9-8-6 | 30 | 3 |
| Mar 12, 2003 | Night | 0-5-3-3 | 11 | 2 |
| Mar 12, 2003 | Day | 5-5-3-5 | 18 | 9 |
| Mar 11, 2003 | Night | 2-7-2-1 | 12 | 3 |
| Mar 11, 2003 | Day | 2-5-3-2 | 12 | 3 |