The winning Connecticut Play4 numbers for March 12, 2003 were: day 5-5-3-5; night 0-5-3-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 12, 2003 | Night | 0-5-3-3 | 11 | 2 |
| Mar 12, 2003 | Day | 5-5-3-5 | 18 | 9 |
| Mar 11, 2003 | Night | 2-7-2-1 | 12 | 3 |
| Mar 11, 2003 | Day | 2-5-3-2 | 12 | 3 |
| Mar 10, 2003 | Night | 2-3-5-6 | 16 | 7 |
| Mar 10, 2003 | Day | 3-9-4-8 | 24 | 6 |
| Mar 9, 2003 | Night | 1-6-3-3 | 13 | 4 |
| Mar 8, 2003 | Night | 2-2-4-6 | 14 | 5 |
| Mar 7, 2003 | Night | 0-5-9-0 | 14 | 5 |
| Mar 7, 2003 | Day | 8-4-9-3 | 24 | 6 |
| Mar 6, 2003 | Night | 7-9-8-1 | 25 | 7 |
| Mar 6, 2003 | Day | 5-0-3-3 | 11 | 2 |