The winning Connecticut Play4 numbers for March 6, 2003 were: day 5-0-3-3; night 7-9-8-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 6, 2003 | Night | 7-9-8-1 | 25 | 7 |
| Mar 6, 2003 | Day | 5-0-3-3 | 11 | 2 |
| Mar 5, 2003 | Night | 7-8-0-4 | 19 | 1 |
| Mar 5, 2003 | Day | 0-9-8-7 | 24 | 6 |
| Mar 4, 2003 | Night | 1-8-0-9 | 18 | 9 |
| Mar 4, 2003 | Day | 1-7-7-3 | 18 | 9 |
| Mar 3, 2003 | Night | 7-6-7-6 | 26 | 8 |
| Mar 3, 2003 | Day | 1-9-5-6 | 21 | 3 |
| Mar 2, 2003 | Night | 9-0-2-4 | 15 | 6 |
| Mar 1, 2003 | Night | 0-5-5-6 | 16 | 7 |
| Feb 28, 2003 | Night | 3-2-6-6 | 17 | 8 |
| Feb 28, 2003 | Day | 2-7-1-3 | 13 | 4 |