The winning Connecticut Play4 numbers for March 2, 2003 were: night 9-0-2-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 2, 2003 | Night | 9-0-2-4 | 15 | 6 |
| Mar 1, 2003 | Night | 0-5-5-6 | 16 | 7 |
| Feb 28, 2003 | Night | 3-2-6-6 | 17 | 8 |
| Feb 28, 2003 | Day | 2-7-1-3 | 13 | 4 |
| Feb 27, 2003 | Night | 3-7-9-5 | 24 | 6 |
| Feb 27, 2003 | Day | 9-0-7-8 | 24 | 6 |
| Feb 26, 2003 | Night | 2-7-4-2 | 15 | 6 |
| Feb 26, 2003 | Day | 1-5-3-7 | 16 | 7 |
| Feb 25, 2003 | Night | 4-8-6-2 | 20 | 2 |
| Feb 25, 2003 | Day | 8-6-3-0 | 17 | 8 |
| Feb 24, 2003 | Night | 9-6-7-5 | 27 | 9 |
| Feb 24, 2003 | Day | 5-7-9-9 | 30 | 3 |