The winning Connecticut Play4 numbers for February 17, 2003 were: day 3-7-8-3; night 7-9-3-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Feb 17, 2003 | Night | 7-9-3-9 | 28 | 1 |
| Feb 17, 2003 | Day | 3-7-8-3 | 21 | 3 |
| Feb 16, 2003 | Night | 9-8-6-9 | 32 | 5 |
| Feb 15, 2003 | Night | 8-2-8-2 | 20 | 2 |
| Feb 14, 2003 | Night | 7-2-7-6 | 22 | 4 |
| Feb 14, 2003 | Day | 7-0-3-1 | 11 | 2 |
| Feb 13, 2003 | Night | 0-7-0-2 | 9 | 9 |
| Feb 13, 2003 | Day | 5-1-0-9 | 15 | 6 |
| Feb 12, 2003 | Night | 4-5-5-4 | 18 | 9 |
| Feb 12, 2003 | Day | 1-7-7-2 | 17 | 8 |
| Feb 11, 2003 | Night | 5-5-7-0 | 17 | 8 |
| Feb 11, 2003 | Day | 3-4-8-9 | 24 | 6 |