The winning Connecticut Play4 numbers for February 11, 2003 were: day 3-4-8-9; night 5-5-7-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Feb 11, 2003 | Night | 5-5-7-0 | 17 | 8 |
| Feb 11, 2003 | Day | 3-4-8-9 | 24 | 6 |
| Feb 10, 2003 | Night | 2-4-0-9 | 15 | 6 |
| Feb 10, 2003 | Day | 0-0-7-0 | 7 | 7 |
| Feb 9, 2003 | Night | 3-8-6-6 | 23 | 5 |
| Feb 8, 2003 | Night | 7-9-6-6 | 28 | 1 |
| Feb 7, 2003 | Night | 8-1-6-5 | 20 | 2 |
| Feb 7, 2003 | Day | 6-7-3-3 | 19 | 1 |
| Feb 6, 2003 | Night | 5-0-1-1 | 7 | 7 |
| Feb 6, 2003 | Day | 4-2-2-9 | 17 | 8 |
| Feb 5, 2003 | Night | 8-8-9-9 | 34 | 7 |
| Feb 5, 2003 | Day | 6-3-4-7 | 20 | 2 |